Bug 7475

Summary:	"source" does not work in conjunction with "process substitution"
Product:	Sisyphus	Reporter:	at <at>
Component:	bash	Assignee:	placeholder <placeholder>
Status:	RESOLVED LATER	QA Contact:	qa-sisyphus
Severity:	normal
Priority:	P2	CC:	glebfm, ldv, placeholder, vt
Version:	unstable
Hardware:	all
OS:	Linux
URL:	http://lists.gnu.org/archive/html/bug-bash/2006-01/msg00018.html

Description at@altlinux.org 2005-07-28 05:49:57 MSD

Steps to Reproduce:
$ bash -ec 'cat <(echo echo 1)'
echo 1
$ bash -ec '. <(echo echo 1)'
$ bash -exc '. <(echo echo 1)'
+ . /dev/fd/63
$ ++ echo echo 1

Note that my command prompt is screwed in the last case, i.e. bash exited
before the process substitution was finished.



Expected Results:  
1

Comment 1 Dmitry V. Levin 2005-12-31 02:17:38 MSK

Same happens with bash-3.0

Comment 2 Dmitry V. Levin 2006-01-07 01:11:47 MSK

Same with bash-3.1.1.
Here is an explanation:

$ strace -e trace=file,desc bash -ec '. <(echo echo 1)'
[...]
stat64("/dev/fd/63", {st_mode=S_IFIFO|0600, st_size=0, ...}) = 0
open("/dev/fd/63", O_RDONLY|O_LARGEFILE) = 3
fstat64(3, {st_mode=S_IFIFO|0600, st_size=0, ...}) = 0
read(3, "", 0)                          = 0
close(3)                                = 0

Comment 3 Dmitry V. Levin 2006-01-10 01:42:52 MSK

From Chet Ramey answer:
"The bash source builtin only works with regular files.
This is a limitation that will someday be lifted."

http://lists.gnu.org/archive/html/bug-bash/2006-01/msg00018.html