#7610 – Unable to feed "trap -p" output into a pipe

Bug 7610 - Unable to feed "trap -p" output into a pipe

Summary: Unable to feed "trap -p" output into a pipe

Status:	CLOSED NOTABUG

Alias:	None

Product:	Sisyphus
Classification:	Development
Component:	bash (show other bugs)
Version:	unstable
Hardware:	all Linux

Importance:	P2 normal
Assignee:	placeholder@altlinux.org
QA Contact:	qa-sisyphus

URL:	http://lists.gnu.org/archive/html/bug...
Keywords:

Depends on:
Blocks:

Reported:	2005-08-09 03:33 MSD by at@altlinux.org
Modified:	2006-01-10 01:45 MSK (History)
CC List:	3 users (show)

See Also:

Attachments
Add an attachment (proposed patch, testcase, etc.)

Note You need to log in before you can comment on or make changes to this bug.

Description

at@altlinux.org 2005-08-09 03:33:33 MSD

bash-2.05b$ trap -p
bash-2.05b$ trap "echo ..." EXIT
bash-2.05b$ trap -p EXIT
trap -- 'echo ...' EXIT
bash-2.05b$ trap -p EXIT |wc -l
0
bash-2.05b$

Comment 1

Dmitry V. Levin 2005-12-31 02:21:47 MSK

Same happens with bash-3.0

Comment 2

Dmitry V. Levin 2006-01-07 01:14:29 MSK

Same with bash-3.1.1.

Comment 3

Dmitry V. Levin 2006-01-10 01:45:31 MSK

From Chet Ramey answer:
"Each element of a pipeline is run in a subshell.
Subshells don't traps from their parent."

http://lists.gnu.org/archive/html/bug-bash/2006-01/msg00019.html